March 11, 2025
Summary: Unlock the key to achieving excellent scores in aptitude exams with remarkable finesse! This article discusses concepts and necessary Time and Work Questions for Aptitude Exams 2025.
The concept of time and work is crucial in all aptitude tests.
Over the past ten years, questions based on this idea have frequently appeared in various aptitude tests, including DUJAT, IPMAT, etc.
On average, you will have 2-3 questions based on this topic yearly in the Management Aptitude Entrance examinations.
To ease your preparation, we have compiled the necessary Time and Work Questions for Aptitude Exams 2025 from the previous year's papers and a few self-designed questions by TopRankers faculty.
Time and Work Questions for Aptitude Exams are very important to determine the level of efficiency of a candidate in solving practical problems about productivity and collaboration.
Logical reasoning, mathematical skills, and time management skills are tested through these questions, which are imperative for competitive tests such as IPMAT, CAT, and SSC.
Practice in this topic enhances speed, accuracy, and problem-solving skills, which benefit aspirants in scoring high marks.
These questions should be practised regularly as they enhance concept clarity and confidence levels in solving quantitative sections effectively.
To solve these questions, first, we need to understand the basic concept of work.
Example 1:
If A works in ‘a’ days, then in one day, A does ⇒1/a work.
If B does work in ‘b’ days, then in one day B does ⇒ 1/b work.
So if A and B work together, then their combined work is 1/a + 1/b = (a+b)/ab
Example. If A can do a work in 10 days and B can do the same work in 12 days, then the work will be completed in how many days?
Solution. Total no. of days = (10*12)/(22) = 120/22 = 5.45 days
Instead of taking the total work value as 1 unit of work, we can also look at the total work as the relative percentage of work done in a day. If A does work in 10 days, then he will do 10% of the total work in one day.
Example 2:
A can build a wall in 10 days, B can build it in 5 days, and C can destroy it in 20 days. If they start working, how many days will the work be completed?
Solution:
The net combined work per day = A’s work + B’s work - C’s work
⇒ 10% + 20% - 5%
⇒ 25% in one day
⇒100/25 = 4 days.
The general equation that applies to the Time and Work problem is
⇒ work rate x time = work done
According to this equation, if work done is constant, then the work rate is inversely proportional to time. But if the work done changes, then there is a change in the work rate and time product. If the work is doubled and time is halved, then the work rate is increased by four times.
Example 3:
Twenty men working 8 hours a day can ultimately build a wall of length 200 meters, breadth 10 metres and height 20 metres in 10 days. How many days will 25 men working 12 hours a day be required to build a wall of length 400 meters, breadth 10 metres and height of 15 metres?
Solution:
L1B1H1/ L2B2H2 = m1t1d1/ m2t2d2
(200* 10 * 20) / (400 * 10 * 15) = (20 * 8 *10) / (25 * 12 * d2)
⇒ d2 = 8 days,
Q1. 'A' can do a piece of work in 25 days and B in 20 days. They work together for 5 days, and then 'A' goes away. In how many days will B finish the remaining work?
(a) 17 days (b) 11 days (c) 10 days (d) None of these
Solution
Percentage of work done by A in one day = 100/25 = 4%
⇒ Percentage of work done by A in one day = 100/20 = 5%
⇒ Work done by both of them in 5 days = 4*5 + 5*5 = 45% work.
⇒ work left to be done = 100 - 45 = 55%
⇒ days taken by B to complete 55% work = 55/5 = 11 days.
Hence, option B is the correct choice.
Read: Triangle Questions For Aptitude Exams
Q2. A can do work in 18 days, B in 9 days and C in 6 days. A and B start working together, and after 2 days, C joins them. What is the total number of days taken to finish the work?
(a) 4.33 (b) 4.5 (c) 4.66 (d) None of these
Solution
Percentage of work done by A in one day = 100/18 = 5.55%
⇒ Percentage of work done by A in one day = 100/9 = 11.11%
⇒ Percentage of work done by C in one day = 100/6 = 16.66%
⇒ Work done by A and B in 2 days = 2*5.55 + 2*11.11 = 33.32% work.
⇒ work left to be done = 100 - 33.32 = 66.68%
⇒ all of they took days to complete 66.68% of work = 66.68/33.32 = 2 days.
⇒ Total no. of days = 4 days.
Hence, option D is the correct choice.
Read: Solving Permutation and Combination Questions for Aptitude Exams
Q3. A and B required ten days to complete a job. B and C require 12 days to complete the same job. A and C require 15 days to complete the same job. The number of days required, if all are at work, to complete the job is
(a) 8 days (b) 9 days (c) 6 days (d) 7 days
Solution
Percentage of work done by A and B in one day = 100/10 = 10%
⇒ Percentage of work done by B and C in one day = 100/12 = 8.34%
⇒ Percentage of work done by A and C in one day = 100/15 = 6.66%
⇒ Work done by A, B and C in one day = 2(a + b + c) = 25% ⇒12.5%
⇒ Total no. of days to complete the work= 100/12.5 = 8 days.
Hence, option D is the correct choice.
Read: IPM Aptitude Questions Based on Remainders
Q4. If Ajit can do one-fourth of the work in 3 days and Sujit can do one-sixth of the same work in 4 days, how much will Ajit get if both work together and are paid Rs. 180 in all?
(a) Rs. 120 (b) Rs. 108 (c) Rs. 60 (d) Rs. 36
Solution
Work done by Ajit in one day = 100/4*3 = 8.33.
Work done by Sujit in one day = 100/ 6*4 = 4.167
The ratio of Ajit and Sujit Work ⇒ 8.33: 4.12 ⇒ 2:1
Therefore, Ajit will be paid = 180*2 / 3 = 120.
Hence, option A is the correct choice.
Q5. A can-do work in 9 days. If B is 50% more efficient than A, how many days can B do the same work?
(a)13.5 (b) 4.5 (c) 6 (d) 3
Solution
⇒ Percentage of work done by A in one day = 100/9 = 11.11%
⇒ Percentage of work done by B in one day = 11.11 + 11.11*(.5) = 16.66%
⇒ Total no. of days taken by B to complete the work 100/16.66 = 6 days.
Hence, option C is the correct choice.
Read: Short Tricks to Solve Reading Comprehension in Aptitude Exams
Q6. Two men undertake to do a piece of work for Rs. 200. One alone can do it in 6 days and the other in 8 days. With the help of a boy, they finish it in 3 days. How much is the boy's share?
(a) Rs. 45 (b) Rs. 40 (c) Rs. 30 (d) Rs. 25
Solution
Let the total work be the LCM of 6 and 8, i.e. 24 units.
⇒ Work done by A will be four units per day
⇒ work done by B will be three units per day
⇒ total work be 8 units per day
⇒ therefore, the work done by boys will be 8 - 7 ⇒ 1 unit per day
⇒ the boy will be paid â…› x 200 = Rs. 25.
Hence, option D is the correct choice.
Q7. Together, 10 men and 15 women can complete a work in 6 days. It takes 100 days for one man alone to complete the same work. How many days will one woman alone need to complete the work? (DUJAT 2020)
(a) 90 days (b)225 days (c) 145 days (d) 150 days
Solution:
⇒ Work done by one man in one day ⇒ 100/100 = 1%
⇒ work done by 10 men and 15 women in one day = 100/ 6 = 16.67%
⇒ work done by 10 men in one day = 10 x 1 = 10%
⇒ work done by one women in one day = 6.67 / 15 = .44%
⇒ time taken by one woman to do the complete work = 100/ .44 = 225 days.
Hence, option B is the correct choice.
Q8. A tap can fill a tank in 48 minutes, while another can empty it in 2 hours. If both the taps are opened at 11:40 am, then the tank will be filled at
Solution
⇒ Total volume filled by tap in one hour = 60 / 48 = 1.25 V
⇒ total volume emptied by the tap in one hour = 1/ 2 ⇒ .5V
⇒ net volume filled by the tap in one hour ⇒ 1.25 - .5 ⇒ .75V
⇒ time required to fill the tank = 1 / .75 ⇒ 1.33 hours = 80 minutes
⇒ the tank will be filled at 1:00 pm
Hence, option C is the correct choice.
Read: IPM Aptitude Questions Based on Remainders
Q9. Pipes A, B and C together can fill a tank in 5hrs. Pipe C is twice as fast as pipe B, and pipe B is twice as fast as pipe A. How much time will pipe A alone take to fill the tank?
Solution
⇒ Volume filled by all of them in one hour = â…• V
⇒ ratio of a:b:c = 1:2:4, therefore volume filled by A in one hour ⇒ 1/(5 x 7) ⇒ 1/ 35V
⇒ time required by A to fill the whole tank ⇒ 1/volume filled in one hour ⇒ 35 hours
Hence, option C is the correct choice.
Q10. There are three taps A, B and C in a tank. They can fill the tank in 10hrs, 20hrs and 25 hrs respectively. At first, all of them are opened simultaneously. Then, after 2 hours, tap C is closed, and A and B are kept running. After the 4th hour, tap B is also closed. The remaining work is done by tap A alone. Find the percentage of the work done by tap A itself.
Solution
⇒ Work done by all the taps in one hour = 100/10 + 100/20 + 100/25 = 10 + 5 + 4 = 19%
⇒ Work done by Tap C in 2 hours = 2 x 4 = 8%
⇒ work done by tap B in 4 hours = 5 x 4 = 20%
⇒ work done by Tap A = 100 -( 20 + 8 ) = 72%
Hence, option C is the correct choice.
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11. A group of 8 workers can complete a project in 20 days. If 4 of these workers leave after 8 days, how many more days will it take for the remaining workers to finish the project?
Solution:
The total work to be completed is 8 workers * 20 days = 160 worker days.
In the first 8 days, the completed work is 8 workers * 8 days = 64 worker-days. The remaining work is 160 worker-days - 64 worker-days = 96 worker-days.
Now, the remaining 4 workers will complete the project in 96 worker-days / 4 workers = 24 days.
12. A machine can print 1200 pages in 6 hours. How many pages can it print in 3 hours?
Solution:
The printing rate is 1200 pages / 6 hours = 200 pages per hour.
In 3 hours, the machine can print 200 pages/hour * 3 hours = 600 pages.
Read: Why Should You Choose Management as a Career?
13. Two workers can build a wall in 10 days. How many additional workers are needed to complete the same wall in 5 days?
Solution:
The total work to build the wall is 2 workers * 10 days = 20 worker-days.
To complete the wall in 5 days, the required work is 2 workers * 5 days = 10 worker-days.
The additional workers needed are 10 worker-days / 5 days = 2 workers.
14. A contractor hires 12 painters to complete a project in 15 days. After 6 days, 4 painters leave the job. How many more painters should be employed to finish the project on time?
Solution:
The total work to be completed is 12 painters * 15 days = 180 painter-days. The completed work in the first 6 days is 12 painters * 6 days = 72 painter-days.
The remaining work is 180 painter-days - 72 painter-days = 108 painter-days.
Now, 8 painters are left to complete the project. To finish the remaining work in time, 108 painter-days / 8 painters = 13.5 days.
We cannot hire half a painter, so it's better to round up to 14 days. So, no additional painters are needed.
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15. A factory can produce 3000 product units in 12 days. How many units can it deliver in 20 days?
Solution:
The production rate is 3000 units / 12 days = 250 units per day.
In 20 days, the factory can produce 250 units/day * 20 days = 5000 units.
Read: IPM Aptitude Questions & Answers Based on Cross Multiplication
Practicing Time and Work Questions for Aptitude Exams enhances problem-solving speed and accuracy, boosting overall exam performance.
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