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IPMAT Indore 2024 - QA (MCQ) Q33 Explanation
November 26, 2024
Explanation:
(a) Option (a) 3^200=(3^2)^100 = 9^100
Option (c) 4^100
Option (d) 2^300 = (2^3)^100 = 8^100
Clearly, among the option (a), (c) and (d) the exponent is same. So, the option with largest base will be largest. So, among these three options, option (a) is largest.
Now option (b) is 2^100+3^100 < 3^100 + 3^100
Or, 2^100+3^100 < 2x 3^100
And, 2x3^100 is certainly less than 3^200 i.e. option (a)
That means, option (b) is less than option (a).
∴ Option(a) is the highest.