November 24, 2024
Explanation:
(a) In △ABD, ∠ ABD = ∠ ACD = x (let′s say) (∵ AB = AC)
Now,take ∠CDE = y
∠AED =x+y (Using exterior angle property)
∴ ∠ADE =x+y (ADE is an isosceles △,AD = AE)
∴ ∠DAE =180° − (2x+2y)
Using angle sum property, in △ ABC
A+∠B+∠C=
⇒x+(30°+180−2x−2y)+x=180°
⇒2y=30°
⇒ y= ∠CDE = 15°. Ans