November 23, 2024
Explanation:
(a) Given that |𝑥+1|+(𝑦+2)^2 = 0
Sum of an absolute value & a perfect square value can be equal to 0 only when each of these terms is equal to 0.
∴ |𝑥+1| = 0
⇒ 𝑥 = −1 & (𝑦+2)^2 = 0 ⇒ y + 2 = 0 ⇒ y = −2
Putting the values of x and y in the equation,ax−3ay = 1,
we get a (-1)- 3a (-2) = 1
⇒ -a + 6 a = 1
⇒ a = 1 5 Ans.