November 22, 2024
Explanation:
(d) Let CD= height of the pole BD=x
In ∆ DBC,tan 45°= h/x =1
∴ h=x In
∆ DAC, tan 30°= h/x+20 = 1/√3
⇒ x+20 = h√3
Put h = x in the above equation, h+20 = h√3
⇒h(√3−1) = 20
⇒ h = 20/√3−1 ×√3+1/√3+1 = 20(√3+1)/2 = 10(√3+1) Ans.