IPMAT Indore 2023 - QA (SA) Q9 Explanation

Explanation:

(1442)

Given that a, b, c and d are positive integer such that a + b + c + d = 2023

Also, a: b = 2: 5 & c: d = 5: 2

Let a = 2x & let b = 5x and c = 5y and d = 2y.

Putting these values in the given equation, we get

2x + 5x + 5y + 2y = 2023

7x + 7y = 2023

7 (x + y) = 2023

(x + y) = 289 ------ (1)

We have to find maximum value of a + c i,e. 2x + 5y

As the coefficient of y is 5 (which is greater than the coefficient of x), the value of y should be as high as possible, from eqn….(1), y can be as high as 288 & x can be 1.

Substituting these values in 2x + 5y, we get

2x1 + 5x288 = 1442. Ans.