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IPMAT Indore 2024 - QA (MCQ) Q27 Explanation
November 25, 2024
Explanation:
(b) Note: Number of digits in any number, N = (Integral part i.e. Characteristic of log N) + 1
For number of digits of 2^2024,
log 2^2024 = 2024 log 2 = 2024 x 0.301 = 609.28
Number of digits in 2^2024 = 609 + 1 = 610
For number of digits of 5^2024,
log5 2024 = 2024 log5 = 2024 x 0.699 = 1414.71
Number of digits in 5^2024 = 1414+ 1 = 1415
So, the total digits when 2^2024 + 5^2024 are written out consecutively is 610 + 1415 = 2025. Ans.