IPMAT Indore 2023 - QA (MCQ) Q36 Explanation

Explanation:

(a)

Let S and E be the start and end point of the person.

△SME will be a right angle triangle.

We have to find SE.

Using Pythagoras theorem, SE^2 = SM^2 + ME^2 …………. (i)

Here, SM = net distance travelled in east direction (towards right).

& ME = net distance travelled in south direction (downwards).

SM = 32 – 8 + 2 –1/2 + ⋯∞ = 32/ 1−(−1/4) = 32 × 4/5 ( using 𝑆∞ = 𝑎/1−r) ME = 16 − 4 + 1 − 1/4 + ⋯−∞

= 16/1−(−1/4) = 16 × 4/5 ( using 𝑆∞= 𝑎/1−r )

Substitute the value of SM & ME in eqn.(i), we get,

SE =√(32×4/5)T2 + (16×4/5)^2

= 4 × 16/5 √4+1

= 64/5 ⋅√5 = 64/√5 ⋅Ans.